SOLUTION: find a real number that exceeds its cube by 2.
Algebra.Com
Question 97253This question is from textbook
: find a real number that exceeds its cube by 2.
This question is from textbook
Found 2 solutions by Nate, edjones:
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
x = x^3 + 2
Obviously, the number is negative.
Between -2 and -1 ...
About -1.52
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
x=x^3+2
x^3-x+2=0 (no factors)
x=-1.5213797 (TI calculator)
x^3=-3.5213797
Ed
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