SOLUTION: Find three consecutive integers where 4 more then twice the first is 12 more than the third.

Algebra.Com
Question 96967: Find three consecutive integers where 4 more then twice the first is 12 more than the third.
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Find three consecutive integers where 4 more then twice the first is 12 more than the third.
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1st: x
2nd: x+1
3rd: x+2
EQUATION:
2x+4=x+2+12
x = 10
x+1 = 11
x+2 = 12
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Cheers,
Stan H.

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