Question 967719:
One number is 7 times a first number. A third number is 100 more than the first. If the sum of the three numbers is 793, find the numbers. Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! X IS THE FIRST NUMBER
7X IS THE SECOND NUMBER
X=X+100 IS THE THIRD NUMBER
X+7X+X+100=793
9X=793-100
9X=693
X=693/9
X=77 ANS
7*77=539 ANS.
77+100=177 ANS.
PROOF:
77+539+177=793
793=793