SOLUTION: Eight times the sum of the digits of a certain two-digit number exceeds the number by 19. The tens digit is two less than the units digit. Find the number.
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Question 956600: Eight times the sum of the digits of a certain two-digit number exceeds the number by 19. The tens digit is two less than the units digit. Find the number.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Eight times the sum of the digits of a certain two-digit number exceeds the number by 19. The tens digit is two less than the units digit. Find the number.
***
let u=units digit
let t=tens digit
t=u-2
..
8(t+u)=10t+u+19
8t+8u=10(u-2)+u+19
8(u-2)+8u=10u-20+u+19
8u-16+8u=10u-20+u+19
5u=15
u=3
t=u-2=1
number=10t+u=10+3=13
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