SOLUTION: Player A led a baseball league in runs batted in for the 2006 regular season. Player B, who came in second to player A had 16 fewer runs batted in for the 2006 regular season. Toge

Question 952230: Player A led a baseball league in runs batted in for the 2006 regular season. Player B, who came in second to player A had 16 fewer runs batted in for the 2006 regular season. Together these two players brought home 242 runs during the season. How many runs batted did player A and B each account for?
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
A=Player A runs; B=Player B runs=A-16
A+B=242 Substitute for B.
A+A-16=242 Add 16 to each side.
2A=258 Divide each side by 2.
A=129 ANSWER 1: Player A batted in 129 runs.
B=A-16=129-16=113 ANSWER 2: Player B batted in 113 runs
CHECK:
A+B=242
129+113=242
242=242
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