SOLUTION: Find three consecutive integers such that three times the sum of the first and the last is 552. Help would be appreciated, been trying to solve it for about a day.

Question 948696: Find three consecutive integers such that three times the sum of the first and the last is 552. Help would be appreciated, been trying to solve it for about a day.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Find three consecutive integers
n, (n+1), (n+2)
:
such that three times the sum of the first and the last is 552.
3(n + (n+2)) = 552
3(2n + 2) = 552
6n + 6 = 552
6n = 552 - 6
6n = 546
n = 546/6
n = 91 is the 1st integer, then obviously, 92 and 93
:
:
Check this
3(91 + 93) =
3 * 185 = 552
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