SOLUTION: find three consecutive odd integers such that 4 times the sum of the last two is 2 greater than 10 times the first.

Question 944304: find three consecutive odd integers such that 4 times the sum of the last two is 2 greater than 10 times the first.
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
Let F,S, and T be first, second and third odd integers
S=F+2, T=F+4
10F+2=4(S+T)
10F+2=4S+4T Substitute for S and T, solve for F
10F+2=4(F+2)+4(F+4)
10F+2=4F+8+4F+16 Subtract 8F from each side
2F+2=24 Subtract 2 from each side
2F=22
F=11 ANSWER First integer is 11
S=F+2=13 ANSWER Second integer is 13
T=F+4=15 ANSWER Third integer is 15
CHECK
10F+2=4(S+T)
10(11)+2=4(13+15)
110+2=4(28)
112=112

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