SOLUTION: Find three consecutive integers such that the sum of the first and twice the third is one more than three times the second.
Algebra.Com
Question 94357: Find three consecutive integers such that the sum of the first and twice the third is one more than three times the second.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
X(X+1)(X+2) ARE THE 3 NUMBERS
X+2(X+2)-1=3(X+1)
X+2X+4-1=3X+3
3X-3X=3-4+1
0=0 THE FIRST OR LOWEST INTERGER IS 0.
0+1=1 SECOND
0+2=2 THIRD
PROOF
0+2(0+2)-1=3(0=1)
0+0+4-1=0+3
3=3
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