SOLUTION: The sum of the squares of two digits of a positve integral number is 6 and the number is 9 times the sum of its digits. Find the number.
Algebra.Com
Question 941849: The sum of the squares of two digits of a positve integral number is 6 and the number is 9 times the sum of its digits. Find the number.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The sum of the squares of two digits of a positve integral number is 6
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There are no 2 integers such that a^2 + b^2 = 6.
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