SOLUTION: Find three consecutive odd integers such that the sum of twice the first integer and three times the second integer is seven more than twice the third integer This is what I tri

SOLUTION: Find three consecutive odd integers such that the sum of twice the first integer and three times the second integer is seven more than twice the third integer This is what I tri

Algebra.Com

Question 940889: Find three consecutive odd integers such that the sum of twice the first integer and three times the second integer is seven more than twice the third integer
This is what I tried..
2(x) +3(x+2)+7=2(x+4)
2x+3x+6+7=2x+8
5x+13=2x+8
3x+13=8
3x=-5

Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
The correct equation is 2x + 3(x+2) = 7 + 2(x+4) (read carefully!)

Try solving again.
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