SOLUTION: Find the bigger 2 consecutive positive integers such that the sum of their squares is 613?
Algebra.Com
Question 938048: Find the bigger 2 consecutive positive integers such that the sum of their squares is 613?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the bigger 2 consecutive positive integers such that the sum of their squares is 613?
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613/2 =~ 306
sqrt(306) =~ 17.5
--> 17 & 18
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