SOLUTION: Find three consecutive positive integers such that the sum of the squares of the largest two is 181.
thanks
Algebra.Com
Question 931637: Find three consecutive positive integers such that the sum of the squares of the largest two is 181.
thanks
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
three consecutive positive integers: x, x+1, x+2
(x+1)^2 + (x+2)^2 = 181
2x^2 + 6x + 5 = 181
2x^2 + 6x -176 = 0
x^2 + 3x - 88 = 0 (tossing out negative solution for positive integers)
(x+11)(x-8)= 0
x = 8
.......
The three consecutive positive integers are: 8,9,10
And...checking
81 + 100 = 181
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