SOLUTION: Find three consecutive positive integers such that the product of the first two is 22 less than 11 times the third

Question 931428: Find three consecutive positive integers such that the product of the first two is 22 less than 11 times the third
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find three consecutive positive integers such that the product of the first two is 22 less than 11 times the third
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1st: x-1
2nd: x
3rd: x+1
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Equation:
(x-1)x = 11(x+1)-22
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x^2-x = 11x-11
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x^2 - 12x + 11 = 0
(x-11)(x-1) = 0
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x = 11 or x = 1
Positive solution:
x-1 = 10
x = 11
x+1 = 12
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Cheers,
Stan H.
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