SOLUTION: he sum of two no. is 68 when the larger no. is divided by the smaller one. we get 2 as quotient and 5 as remainder. write the numbers.....??

Question 928108: he sum of two no. is 68 when the larger no. is divided by the smaller one. we get 2 as quotient and 5 as remainder. write the numbers.....??
Found 2 solutions by Alan3354, ptfile:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
x + y = 68
y/x = 2 + 5/x -- Multiply by x --> y = 2x + 5
----
x + (2x+5) = 68
x = 21
y = 47
Was that a mystery?

Answer by ptfile(81) (Show Source): You can put this solution on YOUR website!
Let 68-x = Larger Number
x = Smaller Number
The sum of two no. is 68.
68-x + x = 68
When the larger no. is divided by the smaller one, we get 2 as quotient and 5 as remainder.
(68-x)/x = (2)+(5/x)
(68-x)/x = (2x/x)+(5/x)
Multiply both side by x
68-x = 2x+5
63 = 3x
21 = x
Substitute x for 21
68 - 21 = 47
The Larger number is 47 while the smaller number is 21.
Check
47 + 21 = 68
47/21 = 2 remainder 5

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