SOLUTION: Eight times the first of three consecutive odd integers is ten more than twice the second.

Question 92593: Eight times the first of three consecutive odd integers is ten more than twice the second.
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
Eight times the first of three consecutive odd integers is ten more than twice the second.
ANY INTEGER IS N
EVEN NUMBER IS 2N
ODD INTEGER IS 2N+1
NEXT ODD INTEGER IS 2N+1+2=2N+3
THE NEXT ODD INTEGER IS 2N+3+2=2N+5
8 TIMES THE I = 8(2N+1)=16N+8
TWICE THE SECOND = 2(2N+3)=4N+6
TEN MORE =4N+6+10=4N+16.............HENCE
16N+8=4N+16
16N-4N=16-8
12N=8
N=8/12=......THERE IS NO SOLUTION.......PLEASE CHECK THE DATA IN THE PROBLEM
FOR ANY MISTAKES IN TYPING.

RELATED QUESTIONS
what is eight times the first of three consecutive odd integers is ten more than twice... (answered by Electrified_Levi)

five times the smallest of three consecutive odd integers is ten more than twice the... (answered by Nate)

Five times the smallest of three consecutive odd integers is ten more than twice the... (answered by checkley77)

Find three consecutive odd integers such that the sum of twice the first and three times... (answered by josmiceli)

Find two consecutive odd integers such that twice the first is three more than the... (answered by stanbon)

Forty eight more than the second of three consecutive odd integers is the sum of the... (answered by ankor@dixie-net.com)

find three consecutive odd integers such that 12 more than twice the sum of the first and (answered by lwsshak3)

three times the first of three consecutive odd integers is 3 more than twice the third.... (answered by KMST)

Three times the first of three consecutive odd integers is 3 more than twice the third.... (answered by ankor@dixie-net.com)