SOLUTION: the product of two consecutive positive integers is 80 more than 15 times larger the number

Question 925230: the product of two consecutive positive integers is 80 more than 15 times larger the number
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x = larger integer
y = smaller integer
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xy = 15x + 80
x = y + 1
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xy = 15x + 80
(y + 1)y = 15(y + 1) + 80
yy + y = 15y + 15 + 80
yy - 14y - 95 = 0
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the above quadratic equation is in standard form, with a=1, b=-14 and c=-95
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
1 -14 -95
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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the quadratic has two real roots at:
---
y = 19
y = -5
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the negative root doesn't fit the problem statement, so use the positive root:
---
answer:
y = 19
x = 20
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php
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