SOLUTION: a number between 10 and 100 is 8 times the sum of digits.If 45 is decreased from it the result equals the number formed by interchanging its digits.Find the number.
Algebra.Com
Question 923806: a number between 10 and 100 is 8 times the sum of digits.If 45 is decreased from it the result equals the number formed by interchanging its digits.Find the number.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
8(t+ u) = 10t + u
u =
.......
10t + u - 45 = 10u + t
9t -9u = 45
(63/7)t-9(2/7)t = 45
(45/7)t = 45
t = (7/45)45
t = 7 and u = 2
Number is
and...checking
72 - 45 = 27
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