SOLUTION: in a three-digit number, the hundreds digit is equal to the tens digit and is 2 more than the ones digit. The number formed by reversing the digits is 19 times the sum of the digit

Question 919569: in a three-digit number, the hundreds digit is equal to the tens digit and is 2 more than the ones digit. The number formed by reversing the digits is 19 times the sum of the digits. Find the original number
Answer by JoelSchwartz(130) (Show Source): You can put this solution on YOUR website!
h=hundreds digit
t=tens digit
u=ones digit
h=t
h=2+u
19(t+h+u)=100u+10t+h
19(2+u+2+u+u)=100u+10(2+u)+2+u
19(3u+4)=100u+20+10u+2+u
57u+76=111u+22
54=111u-57u
54=54u
u=1
h=3
t=3
19(7)=100+30+3
133=133
100h+10t+u
300+30+1=331
The original number is 331
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