SOLUTION: I have tried solving this problem several times and still cannot get the right answer. The problem is: Find two consecutive integers such that 4 times the smaller exceeds the large

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Question 914556: I have tried solving this problem several times and still cannot get the right answer. The problem is: Find two consecutive integers such that 4 times the smaller exceeds the larger by 44?
Found 2 solutions by JoelSchwartz, MathTherapy:
Answer by JoelSchwartz(130)   (Show Source): You can put this solution on YOUR website!
x=smaller number
y=larger number
y is the first whole number after x
4x=44+y
y=x+1
4x=44+1+x
3x=45
x=15
y=16
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

I have tried solving this problem several times and still cannot get the right answer. The problem is: Find two consecutive integers such that 4 times the smaller exceeds the larger by 44?


Let smaller number be S

Then larger number = S + 1

Therefore, 4S = S + 1 + 44

4S = S + 45

4S - S = 45

3S = 45

S, or smaller number = , or 

Larger number: 15 + 1, or  

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