SOLUTION: find two consecutive integers such that the larger is nine more than twice the smaller.

SOLUTION: find two consecutive integers such that the larger is nine more than twice the smaller.

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Question 912660: find two consecutive integers such that the larger is nine more than twice the smaller.

Answer by JulietG(1812) (Show Source): You can put this solution on YOUR website!
a = b+1 (consecutive)
a = 2b+9
b+1 = 2b+9
1 = b + 9
b = -8
If the smaller is -8, then the larger is -7
Twice the smaller is -16 +9 = -7
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