SOLUTION: Four times a first number decreased by a second number is 20. The first number increased by three times the second number is 31. Find the numbers.
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Question 912561: Four times a first number decreased by a second number is 20. The first number increased by three times the second number is 31. Find the numbers.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
3(4x - y = 20)
x + 3y = 31
13x = 91
x = 7 and y = 8
And...checking
7 + 24 = 31
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