SOLUTION: There are three consecutive integers such that the sum of the first and second integers decreased by the third integer will result in 68. What are the integers?

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Question 91113: There are three consecutive integers such that the sum of the first and second integers decreased by the third integer will result in 68. What are the integers?
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
LET X, X+1 & X+2 BE THE 3 NUMBERS.
X+(X+1)-(X+2)=68
X+X+1-X-2=68
X-1=68
X=68+1
X=69 ANSWER FOR THE FIRST NUMBER
X+1=70
X+2=71
PROOF
69+70-71=68
139-71=68
68=68