SOLUTION: the sum of the square of two number is 39, the first number being one less their twice the second number. determine the numbers.

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Question 909856: the sum of the square of two number is 39, the first number being one less their twice the second number. determine the numbers.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
(2x-1)^2 + x^2 = 39
4x^2 - 4x + 1 + x^2 = 39
5x^2 - 4x - 38 = 0
x = 3.18567765543682, -2.38567765543682
find corresponding values for (2x-1)to determine the number pairs.
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=776 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 3.18567765543682, -2.38567765543682. Here's your graph:
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