SOLUTION: Find the smallest of three consecutive even integers such that three times the first integer is eight more than the sum of the second and the third.

Algebra.Com
Question 900401: Find the smallest of three consecutive even integers such that three times the first integer is eight
more than the sum of the second and the third.

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi
three consecutive even integers x, x+2, x+4
3x = 2x+6 + 8
x = 14
the three consecutive even integers are: 14, 16, 18
And..
42 = 34 + 8
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