SOLUTION: Find three consecutive even integers such that three times the first plus six times the second is equall to ten times the third.

Question 8955: Find three consecutive even integers such that three times the first plus six times the second is equall to ten times the third.
Answer by bonster(299) (Show Source): You can put this solution on YOUR website!
#1: x
#2: x+2
#3: x+4

three times the first plus six times the second is equall to ten times the third.

3(x) + 6(x+2)=10(x+4)
3x+6x+2=10x+40
9x+2=10x+40 ..........................subtract 9x from both sides
(9x+2)-9x=(10x+40)-9x
2=x+40 .......................subtract 40 from both sides
(2)-40=(x+40)-40
-38=x

#1: x =-38
#2: x+2=-38+2=-36
#3: x+4=-38+4=-34

The three numbers are -38, -36, -34

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