SOLUTION: a positive number is divided into two parts such that the sum of the squares of the two parts is 20.the square of the larger part is 8 times the smaller part. taking x as the small

Question 887984: a positive number is divided into two parts such that the sum of the squares of the two parts is 20.the square of the larger part is 8 times the smaller part. taking x as the smaller part of the two parts,find the number
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
a positive number is divided into two parts such that the sum of the squares of the two parts is 20.
x^2 + y^2 = 20
:
the square of the larger part is 8 times the smaller part.
y^2 = 8x
:
taking x as the smaller part of the two parts, find the number
In the 1st equation replace y^2 with 8x
x^2 + 8x = 20
x^2 + 8x - 20 = 0
Factors to
(x-2)(x+10) = 0
the positive solution
x = 2,
therefore
y =
y = 4
:
4 and 2 are the two numbers
:
:
Check: 4^2 + 2^2 = 20
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