SOLUTION: find three consecutive even numbers such that the sum of the first and the last numbers exceeds the second number by 10

Question 887103: find three consecutive even numbers such that the sum of the first and the last numbers exceeds the second number by 10
Answer by JulietG(1812) (Show Source): You can put this solution on YOUR website!
B = A+2 (consecutive and even)
C = A+4
A + C = B + 10 (the sum of the first and the last numbers exceeds the second number by 10)
Substitute the known values of B & C from the top equations into the bottom.
A + C = B + 10
A + (A+4) = (A+2) + 10
Add
2A + 4 = A + 12
Subtract A from each side
A + 4 = 12
Subtract 4 from each side
A = 8
.
If A = 8, then B = 10, and C = 12
8 + 12 = 10 + 10
20 = 20
Success!
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