SOLUTION: The sum of three numbers is 121. The third number is 4 times the first. The first number is 5 more than the second. What are the numbers ?

Question 882546: The sum of three numbers is 121. The third number is 4 times the first. The first number is 5 more than the second. What are the numbers ?
Found 2 solutions by Edwin McCravy, tajar:
Answer by Edwin McCravy(20056) (Show Source): You can put this solution on YOUR website!

Let the second number = x

The first number is 5 more than the second.

The first number = x+5

The third number is 4 times the first.

The third number = 4(x+5)

The sum of three numbers is 121.

x + x+5 + 4(x+5) = 121 Solve and get x = 16 The first number = x+5 = 16+5 = 21 The second number = x = 16 The third number = 4(x+5) = 4(16+5) = 4(21) = 84 Edwin

Answer by tajar(5) (Show Source): You can put this solution on YOUR website!
RULE to use: Translate word problem into algebraic equations.
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