SOLUTION: Find two consecutive integers whose product is 3 less than the square of the smaller number.
Algebra
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Question 881762
:
Find two consecutive integers whose product is 3 less than the square of the smaller number.
Answer by
ewatrrr(24785)
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Hi
x(x+1) = x^2-3
x^2 +x = x^2 - 3
x = -3
Integers are: -3, -2
and...
6 = 9-3
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