SOLUTION: Find two consecutive integers whose product is 3 less than the square of the smaller number.

Algebra.Com
Question 881762: Find two consecutive integers whose product is 3 less than the square of the smaller number.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi
x(x+1) = x^2-3
x^2 +x = x^2 - 3
x = -3
Integers are: -3, -2
and...
6 = 9-3
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