SOLUTION: The sum of three numbers is 131 . The second number is 4 times the third. The third number is 7 more than the first . What are the numbers?

Algebra.Com
Question 880024: The sum of three numbers is 131 . The second number is 4 times the third. The third number is 7 more than the first . What are the numbers?
Answer by rfer(16322)   (Show Source): You can put this solution on YOUR website!
x+x+7+4(x+7)=131
6x+35=131
6x=131-35
6x=96
x=96/6
x=16
x+7=23
4(x+7)=92

RELATED QUESTIONS

The sum of three numbers is 119. The second number is 4 times the third. The third number (answered by Edwin McCravy)
The sum of three numbers is 92. The second number is 10 more than the first. The third... (answered by josgarithmetic)
The sum of three numbers is 144. The second number is 6 more than the first . The third... (answered by CubeyThePenguin)
The sum of three numbers is 121. The third number is 4 times the first. The first number... (answered by Edwin McCravy,tajar)
The sum of three numbers is 129 . The third number is 4 times the first. The first (answered by MathLover1)
the sum of three numbers is 66. the third number is 9 more than the first. the second... (answered by timvanswearingen)
The sum of three numbers is 74. The first number is 10 more than the third. The second... (answered by josgarithmetic)
The sum of three numbers is 104. The second number is 3 times the third. The third number (answered by josgarithmetic)
The sum of three numbers is 108. The second number is 5 times the third. The first number (answered by josgarithmetic)