SOLUTION: find four consecutive integers with a suum of 196
Algebra
.Com
Question 867110
:
find four consecutive integers with a suum of 196
Answer by
ewatrrr(24785)
(
Show Source
): You can
put this solution on YOUR website!
Hi
n + (n+1)+(n+2)+(n+3) = 196
4n + 6 = 196
4n = 190
n = 47.5 There are NONE
RELATED QUESTIONS
Find four consecutive even integers with a sum of 196. A rectangle has width 52 units...
(answered by
ankor@dixie-net.com
)
Find four consecutive even integers with a sum of 196. A rectangle has width 52 units...
(answered by
CubeyThePenguin
)
find four consecutive even integers whose sum is...
(answered by
kmcruz09
)
Find four consecutive odd integers whose sum is...
(answered by
bucky
)
find four consecutive odd integers whose sum is...
(answered by
stanbon
)
Find four consecutive odd integers with a sum of 464.
(answered by
JulietG
)
The sum of Three consecutive even integers is 196. Find the largest of these...
(answered by
drk,solver91311,MRperkins
)
find four consecutive even integers with the sum of...
(answered by
richwmiller
)
Find four consecutive odd integers have a sum of 120. What are the...
(answered by
checkley77,stanbon
)