SOLUTION: find four consecutive integers with a suum of 196

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Question 867110: find four consecutive integers with a suum of 196
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
n + (n+1)+(n+2)+(n+3) = 196
4n + 6 = 196
4n = 190
n = 47.5 There are NONE
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