SOLUTION: write an equation in standard form of the line that passes through the point P(6,-1) and is perpendicular to the line described by the equation -2x + 3y = -6

Question 861427: write an equation in standard form of the line that passes through the point P(6,-1) and is perpendicular to the line described by the equation -2x + 3y = -6
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
This is how standard form equation for a line works:
, standard form.
Solve for y.

, slope-intercept form.

The slope is and the y-intercept is .

What you should know about perpendicular lines:
If two lines are perpendicular and their slopes are and , then .

Returning to you given equation and to find line perpendicular containing P(6,-1):
The line perpendicular to the given is , and knowing that this new line must contain the point (6,-1), use those coordinates to compute c.
.
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