SOLUTION: Two positive numbers differ by 4. If the sum of their reciprocals is 2/3, find these two numbers.

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Question 860417: Two positive numbers differ by 4. If the sum of their reciprocals is 2/3, find these two numbers.
Answer by ben720(159)   (Show Source): You can put this solution on YOUR website!
If the two positive numbers differ by four,
Let x = 1st number and x+4 = 2nd.
The sum of their reciprocals, equals

To isolate x, first multiply both sides by x(x+4)

Simplify

Multiply both sides by 3

Subtract (6x+12) from both sides

Use the quadratic formula

Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=100 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 2, -3. Here's your graph:


As shown by this solver, the answers for x are either 2 or -3.
However, as both numbers must be positive, it must be 2.
Your answers are 2 and 6 (as 2+4=6)

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