Hi,

log2 (y+1) + log2 (3y-1) = 5 

     (y+1)(3y-1)) = 2^5

     3y^2 + 2y - 1 = 32

     3y^2 + 2y - 33 = 0

x =  (Tossing out this negative root as Extraneous)

x =

 

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