SOLUTION: Log5 (y+ 1) - log5 8 = log5 (y- 3) - log5 6

Algebra.Com
Question 854913: Log5 (y+ 1) - log5 8 = log5 (y- 3) - log5 6
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Log5 (y+ 1) - log5 8 = log5 (y- 3) - log5 6
Log5 (y+ 1) - log5 8 - log5 (y- 3) + log5 6 = 0
Log5 6(y+ 1)/8(y-3)= 0

6y + 6 = 8y - 24
30 = 2y
15 = y
RELATED QUESTIONS

Condense the expression. 1/3 log5 8-1/2 log5 x = 4 log5... (answered by Alan3354)
Simplify 1/3(log5 x – log5 3 + 2log5 y). (answered by lwsshak3,stanbon)
log5(log5... (answered by jsmallt9)
log5(4)+log5(3) (answered by edjones)
log5 Y^2 + log5 Y^0.5 =... (answered by ankor@dixie-net.com)
Express as a sum, difference, and product of logarithms, without using exponents. log5 (answered by Alan3354)
log5(x+6)+log5(X+2)=1 (answered by stanbon)
log5 (x+3) + log5 (x-1) =... (answered by mouk)
Log5 (x+4) = 3+log5... (answered by Fombitz)