SOLUTION: Find two numbers whose diﬀerence is 8, and the sum of twice the ﬁrst and 3 times the second is 32.

SOLUTION: Find two numbers whose diﬀerence is 8, and the sum of twice the ﬁrst and 3 times the second is 32.

Algebra.Com

Question 844188:
Find two numbers whose diﬀerence is 8, and the sum of twice the ﬁrst and 3 times the second is 32.
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
X-Y=8 [MULTIPLY BY 3 & ADD]
2X+3Y=32
3X-3Y=24 ADD
-----------
5X=56
X=56/5
X=11.2
11.2-Y=8
-Y=8-11.2
-Y=-3.2
Y=3.2
PROOF:
2*11.2+3*3.2=32
22.4+9.6=32
32=32
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