SOLUTION: the sum of two digit no is 80 if the largest no exceed 4 times the smaller no by 5 then smaller no is
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Question 840110: the sum of two digit no is 80 if the largest no exceed 4 times the smaller no by 5 then smaller no is
Answer by isma95fb(6) (Show Source): You can put this solution on YOUR website!
let number 1 = a
let number 2 = b
a + b = 80------(i)
assume a = largest number
a - 4b = 5------(ii)
using substitution
from eqn i b = 80 - a
a - 4(80 - a) = 5-------(ii)
a + 4a = 325
a = 65
hence b = 15
the smaller number is 15
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