SOLUTION: Show that the square of the sum of two numbers minus the square of their difference is equal to four times their product.

Algebra.Com
Question 828233: Show that the square of the sum of two numbers minus the square of their difference is equal to four times their product.
Answer by Seutip(231)   (Show Source): You can put this solution on YOUR website!
Let a - be the first number
b - be the second number


Just interpret, breathe in breathe out. Tada! Hope that helps!

RELATED QUESTIONS

Show that the square of the sum of two numbers minus the square of their difference is... (answered by TimothyLamb)
there exist two real number x, y such that the product of their sum and difference is... (answered by ikleyn)
there exist two real number x, y such that the product of their sum and difference is... (answered by ikleyn)
find three consecutive integers such that four times their sum is equal to the product of (answered by mananth)
Find three consecutive integers such that four times their sum is equal to the product of (answered by josgarithmetic)
Prove that for any two numbers, the product of their sum and their difference is equal to (answered by Alan3354)
Find two numbers such that their difference is equal to their product and the sum of... (answered by MathLover1)
The sum of the squares of two numbers is 197. The square of their difference is 83. Find... (answered by Alan3354,ankor@dixie-net.com)
If the sum of the squares of two numbers is equal to the square of their sum, then what... (answered by macston)