SOLUTION: Find three consecutive odd integers such that three times the second minus the third is 33 more than the first.

Question 826634: Find three consecutive odd integers such that three times the second minus the third is 33 more than the first.
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
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z = x + 4
y = x + 2
3y - z = x + 33
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put the system of linear equations into standard form:
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x - z = -4
x - y = -2
x - 3y + z = -33
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copy and paste the above linear system in standard form into this matrix-method solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = 31
y = 33
z = 35
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system matrix
1 0 -1
1 -1 0
1 -3 1
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inverse of system matrix
-1 3 -1
-1 2 -1
-2 3 -1
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determinant of system matrix = 1
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Solve and graph linear equations:
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---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
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Solve systems of linear equations up to 6-equations 6-variables:
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