SOLUTION: Help Pls. Need this ASAP. I beg you. . The perimeter of a triangle is 138 units. If the longest side is 10 more than the shortest side, while the 3rd side is 2 less than the

Question 826019: Help Pls. Need this ASAP. I beg you.
.
The perimeter of a triangle is 138 units. If the longest side is 10 more than the shortest side, while the 3rd side is 2 less than the longest side, find the measures of the 3 sides.
Thank you for the one who'll answer this. May God bless you. :*
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The perimeter of a triangle is 138 units. If the longest side is 10 more than the shortest side, while the 3rd side is 2 less than the longest side, find the measures of the 3 sides.
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Let shortest side be "x" units.
Then longest side is "x+10" units.
And 3rd side is "x+10-2" = "x+8" units
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Equation:
x + (x+10) + (x+8) = 138 units
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3x + 18 = 138
3x = 120
x = 40 units (shortest)
x+10 = 50 units (longest)
x+8 = 48 units (3rd side)
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Cheers,
Stan H.
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