SOLUTION: The difference between 2 natural numbers is 4.The sum of their squares is greater than 9 times sum by 8.Find the numbers

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Question 825271: The difference between 2 natural numbers is 4.The sum of their squares is greater than 9 times sum by 8.Find the numbers
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
This is somewhat ambiguous, but here is a try.

x and y are the natural numbers to find.
;
.

The sum of just the two numbers can be substituted to give ,


Going back to x+y=4, y=4-x, so substitute into the circle equation:





'
; unless I made a mistake, this value will not be a Natural Number. Neither will be y Natural.

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

The difference between 2 natural numbers is 4.The sum of their squares is greater than 9 times sum by 8.Find the numbers

Let the larger and smaller of the 2 numbers be L, and S, respectively
Then: L - S = 4______L = 4 + S ----- eq (i)
Also,

---- eq (ii)
------ Substituting 4 + S for L in eq (ii)

______Collecting like-terms
______Combining like-terms
)______Factoring out GCF, 2

(S + 2)(S - 7) = 0
S = - 2 OR S = 7
Since - 2 is NOT a natural number, the smaller of the 2 natural numbers is:
L = 7 + 4 ------ Substituting 7 for S in eq (i)
L = 11, so the larger of the 2 natural number is:
You can do the check!!
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