SOLUTION: Sean's age is 5 years more than twice Doug's age. The sum of their ages is 29. Find each of their ages.

Question 825000: Sean's age is 5 years more than twice Doug's age. The sum of their ages is 29. Find each of their ages.
Answer by y6n3o9p4(20) (Show Source): You can put this solution on YOUR website!
Let S = Sean's age, and D = Doug's age.
Write it out as these equations:

Use the system of elimination to subtract the second equation from the first one and isolate Doug's age.

Plug Doug's age into one of the equations.

Sean's age is 21, and Doug's age is 8.
RELATED QUESTIONS
Jean�s age is 5 years more than twice Lucy�s age. The sum of their ages is 29. How old... (answered by ikleyn)

Phoebe’s age is 5 more than twice her brother’s age 10 years ago. The sum of their... (answered by trevorgiehl)

Mary’s grandmother’s age is 11 years less than 9 times mary’s age. The sum of their (answered by ikleyn)

Jan's age is three years less than twice Tritt's age. The sum of their ages is 30. Find... (answered by josgarithmetic)

NOAHS AGE IS 3 YEARS MORE THAN TWICE TINA'S AGE. the sum of their ages is 24 years old.... (answered by advanced_Learner)

Anne�s age is 5 more than twice Matteo�s age. a) Write an algebraic expression for the... (answered by Cromlix)

Jan's age is 3 years less than twice Tritt`s age. The sum of their ages is 30. (answered by jorel555)

Shelias age is two years more than twice Nicole�s age. The sum of their ages is the same... (answered by josmiceli,MathTherapy)

Zeus and Leto have a son named Apollo. Zeus is five years older than twice his son�s age... (answered by Fombitz)