SOLUTION: The length of a rectangular field is 50 feet less than its width, if the perimeter of the field is 840 feet, find the length of the field show your work

Question 824187: The length of a rectangular field is 50 feet less than its width, if the perimeter of the field is 840 feet, find the length of the field show your work
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
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x = y - 50
2x + 2y = 840
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put the system of linear equations into standard form
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x - y = -50
2x + 2y = 840
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copy and paste the above standard form linear equations in to this (matrix method) solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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answer1:
x= length = 185 ft
y= width = 235 ft
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now solve by substitution:
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2x + 2y = 840
2(y - 50) + 2y = 840
2y - 100 + 2y = 840
4y = 940
y = 235
x = 235 - 50
x = 185
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answer2:
x= length = 185 ft
y= width = 235 ft
NOTE: matrix and substitution methods yield the same result
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Solve quadratic equations, quadratic formula:
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Solve systems of linear equations up to 6-equations 6-variables:
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