SOLUTION: a number, one third of that number, and one fourth of that number are added. the result is 57. what is the original number ?
Algebra.Com
Question 819699: a number, one third of that number, and one fourth of that number are added. the result is 57. what is the original number ?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let number be x
x+x/3 +x/4 = =57
multiply the equation by 12
12x+4x+3x=12*57
19x=12*57
x=12*57/19
x=36
RELATED QUESTIONS
a number one third of that number and one fourth of that number are added. the result is... (answered by mananth)
a number, one fourth of that number, and one third of that number are added. the result... (answered by ankor@dixie-net.com)
A number, half of that number, and one-third of that number are added. The result is 22.... (answered by checkley75)
a number, half of that number, and one-third of that number are added. the result is 22.... (answered by edjones)
a number, half of that number and one third of that number are added the result is 22.... (answered by checkley77)
A number, half of that number, and one-third of that number are added. the result is 22.... (answered by Fombitz)
A number, half of that number, and one third of that number are added. the result is 22.... (answered by sofiyac)
a number, twice that number, and one-third of that number are added. The result is 20.... (answered by stanbon)
A number, twice that number, and one-fourth of that number are added. The result is... (answered by checkley77)