# SOLUTION: Find two consecutive odd integers such that 5 times the first integer is 12 more than 3 times the second. I don't even know how to sow my work to do this or even where to start.

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 Question 81848: Find two consecutive odd integers such that 5 times the first integer is 12 more than 3 times the second. I don't even know how to sow my work to do this or even where to start. I have been muliplying 3's and 5's like a crazy lady, but there are so many numbers in this world!! hehehe So far, I have only managed to guess at an expression for it as 5a - 3b = 12 which might make sense, but I don't think this is how they want you to figure it.Answer by Earlsdon(6287)   (Show Source): You can put this solution on YOUR website!Let the first odd integer be x. The next consecutive odd integer is x+2. 5x = 3(x+2)+12 Five times the first (5x) is (=) 12 more (+12) than three times the second (3(x+2)) 5x = 3x+6 + 12 5x = 3x + 18 Subtract 3x from both sides. 2x = 18 Divide both sides by 2. x = 9 x+2 = 11