SOLUTION: Find two consecutive odd integers such that 5 times the first integer is 12 more than 3 times the second. I don't even know how to sow my work to do this or even where to start.

Question 81848: Find two consecutive odd integers such that 5 times the first integer is 12 more than 3 times the second.
I don't even know how to sow my work to do this or even where to start. I have been muliplying 3's and 5's like a crazy lady, but there are so many numbers in this world!! hehehe
So far, I have only managed to guess at an expression for it as 5a - 3b = 12 which might make sense, but I don't think this is how they want you to figure it.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let the first odd integer be x.
The next consecutive odd integer is x+2.
5x = 3(x+2)+12 Five times the first (5x) is (=) 12 more (+12) than three times the second (3(x+2))
5x = 3x+6 + 12
5x = 3x + 18 Subtract 3x from both sides.
2x = 18 Divide both sides by 2.
x = 9
x+2 = 11
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