SOLUTION: The difference of twice the smaller of two consecutive integers and the larger is 39. find the integers?

Question 808497: The difference of twice the smaller of two consecutive integers and the larger is 39. find the integers?
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
2s - b = 39
b - s = 1
b = 1 + s
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2s - (1 + s) = 39
s - 1 = 39
Answer:
s = 40
b = 41
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