SOLUTION: Divide 72 in to two parts so that the larger part exceeds the smaller by 12 , find the both parts.

SOLUTION: Divide 72 in to two parts so that the larger part exceeds the smaller by 12 , find the both parts.

Algebra.Com

Question 802663: Divide 72 in to two parts so that the larger part exceeds the smaller by 12 , find the both parts.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
if one part is x then other part will be x+12
Their sum = 72
x+x+12=72
2x+12=72
2x+12-12=72-12
2x=60
/2
2x/2 = 60/2
x=30
One part is 30 so the balance is 42 the other part
RELATED QUESTIONS
divide 72 into two parts so that the larger part exceeds the smaller part by 12.find both (answered by vleith)

Divide 140 into two parts so that twice the smaller part 140−𝑥, is 12 more... (answered by jorel1380,josgarithmetic)

Divide rs.350 into two parts such that the half of greater part exceeds the smaller part... (answered by Cromlix)

divide 30 into 2 equal parts such that the square of the smaller part exceeds the other... (answered by checkley77)

divide 224 into two parts such that when the larger part is divided by the smaller part,... (answered by ewatrrr,htmentor)

divide 224 into two parts such that when the larger part is divided by the smaller part,... (answered by robertb)

divide 98 into two parts so that the larger number divided by the smaller yields quotient (answered by oberobic)

Divide 200 into two parts such that the larger part is more than four times the smaller... (answered by josmiceli,MathTherapy)

4. Divide the number 32 in two parts so that one part is 3 times larger than the... (answered by ewatrrr)