SOLUTION: The length of a rectangle is 3 feet less than twice its width. If the perimeter is 54 feet, find the dimensions of the rectangle.
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Question 800238: The length of a rectangle is 3 feet less than twice its width. If the perimeter is 54 feet, find the dimensions of the rectangle.
Answer by waynest(281) (Show Source): You can put this solution on YOUR website!
length (L) = 2w -3
width = w
p = 54
p = 2L + 2w
54 = 2w + 2(2w - 3)
54 = 2w + 4w - 6
54 + 6 = 6w -6 + 6
60 = 6w
60/6 = 6w/6
10 = w
check:
2(10) + 2(2(10) - 3) = 54
20 + 2(17) = 54
20 + 34 = 54
54 = 54
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