SOLUTION: one number exceeds another by 3. the sum of the numbers is 67. what are the numbers?
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Question 794907: one number exceeds another by 3. the sum of the numbers is 67. what are the numbers?
Answer by wilft1(217) (Show Source): You can put this solution on YOUR website!
turn this into an equation
x + x + 3 = 67
subtract 3 from both sides
x + x = 64
combine like terms
2x = 64
divide both sides by 2
x = 32
our first number is 32
second number is x + 3 = 35
32 and 35
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